Q & A with Noxstant

Since Maarten is the go to man for Halo trivia, and since I've been pounding him with questions, I 'm making this thread.

If you have any questions about the physics of halo or anything else, ask away.

Or if someone wants to attempt to pound me with questions, go right ahead.

All right. I'll start with something basic.

When making a custom model for Halo CE, what should you name your model before you link it to the frame gun node?

Well, what a suprise, it's doompig!!

I didn't see you jump towards maarten's Q&A!

Too much emphasis on the trial mods!

Seriously though, when you create a model for CE, (and apply it to an existing gun -lazy!)

it can depend on the application you are using (gmax or mm3d)

For the most part, I would first make my attachments lightwave object files and after skin is added, create overall BMP or Gfx file and then patch it into the bitmap file of a map on halo (just like you did with Zapwinder)

Im at a loss. i just got maya and the program is hard to figure out. how do you create color on objects?

Assuming all ship borne MAC systems have the same muzzle velocity as the Mk.5 Orbital Mac stations (4/10 of lightspeed) what would the the poweroutput per coil need to be for a 6000 Ton Round to reach that velocity if the MAC has 17 coils.

And a bit simpler one I think.
IF a 6000 Ton Round from a MAC hits a Target at 4/10 of the speed of light what would be the force it exerts on the target in NEWTONS. WHat is the amount of Energy transferred into the target in Joules (Kilo, mega, giga, tera doesnt matter)

Just felt like messing with you, nox

Quote :

Assuming all ship borne MAC systems have the same muzzle velocity as the Mk.5 Orbital Mac stations (4/10 of lightspeed) what would the the poweroutput per coil need to be for a 6000 Ton Round to reach that velocity if the MAC has 17 coils.

Well let's see..

(4/10)(180,000 mi sec2) "288,000 km sec2" = 72,000 mi sec2 "115,200 km sec2"

A 6000 ton round = [(12,000 total pounds) + (Ke = 1/2 mv2) "v= m/d" "d = 5 grams3" =

297,461 joules.

72,000 mi sec2 x (297, 461 joules/1 mi sec2) = 2.14 X 10(10) joules overall energy required.

2.14 x 10(10) /17 coils = 1.25 x 10(9) joules of energy required per coil or 1.25 giga joules per coil.

Wow, look at all that text!

Question Number 2:

Quote :

IF a 6000 Ton Round from a MAC hits a Target at 4/10 of the speed of light what would be the force it exerts on the target in NEWTONS. WHat is the amount of Energy transferred into the target in Joules (Kilo, mega, giga, tera doesnt matter)

Since I have worked out the first one, this one will be a cakewalk.

297,461 joules = 297,461 N sec2- (Since the newton was created to correspond to one joule so easier conversions could be made to the force exerted on a mass)

Newton's first law explains why the object (MAC round) in space would keep constant momentum and velocity. Since the mass isn't that close to the speed of light, no changes in mass would occur.

So that makes the amount of energy in joules exerted on a ship : 12.5 giga joules (1.25 x 10(10)]

OWNED - hey, I could probably make use of this information on something.......

Quote :

Im at a loss. i just got maya and the program is hard to figure out. how do you create color on objects?

Sorry, hellsmadcamper, I don't use maya. I use MM3d and gmax (much more practical)

If you want to download a trial of milkshape 3d (fairly decent obj model exporter though not designed specifically for halo), here is a link : http://swissquake.ch/chumbalum-soft/

Or you could download gmax (find it at the filefront website)

Noxstant. wrote:

OWNED - hey, I could probably make use of this information on something.......

That was a tad uncalled for...

BUT YAY FOR NOXSTANT (felt random but wtf)

I owned the equation, not you, maarten. That was a great question.

I was also referring to this thread.

BTW, is that all you have?

Screw it, Noxstant get's an Achievement. Another one. It's called the "In English Please." Achievement. He gets it because of his reply to Maarten's question. Screw, now he has more achievements than me, but not as much G =).

Quote :

Originally Posted by Doompig444:
All right. I'll start with something basic.

I take it from that statement you have something else for me to - "OVERKILL!!"
as well.....

Whats the Airborne Velocity of a unladen swallow?

Figure this one out.

How would a european swallow carry a coconut??

The airbone velocity for an unladed Swallow is approximately 10 meters per second.

A swallow could carry and swallow a coconut if :

- The coconut was shattered into pieces

- the coconut was part of a drink

- if the starship enterprise beamed it into its stomach

ROFL at the Monty Python incorporation.

Noxstant wrote:

The airbone velocity for an unladed Swallow is approximately 10 meters per second.

A swallow could carry and swallow a coconut if :

- The coconut was shattered into pieces

- the coconut was part of a drink

- if the starship enterprise beamed it into its stomach

heheh I guess, but the 1 one would be out of the question, how am I supposed to bang em together??

Well, if you are talking about being stuck on an island without a hammer (or C4, always C4) Then you could drop a large boulder on the coconut.

I was actually talking about banging 2 halves together to simulate horse feet sounds (like in The Holy grail by monty Python)

taht movie was my favoite of all movies...


But I HAVE A QUESTION... Trust me, this one is hard.


1.what is the force in Newtons of 58.14 kg of compressed C-16 (compression ratio 187%)in a soild lead cylinder(closed in one end[where the explosives are]) with a (length 5m long) (inner circ. of 1.086 meters) in space?

2. If there was 30.31 Kg bullet (circumference of 1.08581 m)inside the cylinder with the c-16 when the c-16 exploded, and the bullet left the tube what would the force of the impact of the bullet against another object?

3.what would its terminal velocity be?

4.What would its initial velocity be?

5.How long would it take it to leave the tube and stike a object 100 meters away?


Figure this out, and you will be my hero!

Don't help HMC with her homework xD

its not homework!!!!

I wanna make a videogame when i get older....

and the Math wiz noxstant, all my hard calcuatons would be finished.

Good luck finding an engine to input these specifications. Physics simulator?

Here is the data (large inhale)

1. A lot of unnecessary information.

Force = MA

F = 58.14kg (x)

(X) = 187% compression ratio x standard blast force (270,000 joules - as discovered by me) + 4/10 of light speed (72,000 mi sec 2) =

774,900 joules of force + [ 72,000 x 58.14] 4,960,980

That means 4,960,980 N-1 mi sec2 or 4.9 x 10(6)

2 - 5

I hate to tell you this, but there is a gaping hole in question number 2.

Newton's laws of motion state that for every action there is an equal and opposite reaction.

The bullet with the c-16 would most likely be ionized by the intense heat, but if it was massive enough, the compression of the canister would become too great and a massive explosion would take place, destroying half of the ship.

If you find an engine that you can plug things like this in, could you inform me?

Also, if you do, it will be realistic and what I described will most likely occur. (exhale)

Thank you so much!

No problem. Though be sure when you finish this game, whenever that may be, you send

me a copy, okay?

Same here xD

Of course it probably won't happen for a another 10 years.